In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
6/8, 9/12
Step-by-step explanation:
Answer:
Roughly 5%
Step-by-step explanation:
.05*34.75=1.74
34.75-1.74=33.01
Answer:
Step-by-step explanation:
multiply the 2x by x and 7 and then multiply 3 by x and 7. you will get 2
+14x+3x+21. combine like terms so add 14x to 3x and thats the only like trerms in the equation. so 2x^2+17x+21
Answer:268.08
Step-by-step explanation:
