Answer:question 1)$6.66.67
Question2) Rent and expenses =$760
Rent and expenses are too high for the budget
Step-by-step explanation:
1)$2000×(1/3)= $666.67
2)Rent and expenses =$(650+60+10+20+20)= $760
$2100×(1/3)= $700
Rent and expenses should not exceed one third of $2100, which is $700 but it exceeded by$60. Therefore budget is too high.
I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)
I don’t know if I’m right but yea...
Alright, so since anything can be squared, the domain is (-inf, inf)
Answer:
1 solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
9(z + 8) = -9z - 72
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 9: 9x + 72 = -9z - 72
- Add 9z to both sides: 18z + 72 = -72
- Subtract 72 on both sides: 18z = -144
- Divide 18 on both sides: z = -8
Here we see that we will get only 1 solution for <em>z</em>.
Answer:
d = 40/7
Step-by-step explanation:
Solve for d:
0.544444 = 28/(9 d)
0.544444 = 49/90:
49/90 = 28/(9 d)
49/90 = 28/(9 d) is equivalent to 28/(9 d) = 49/90:
28/(9 d) = 49/90
Take the reciprocal of both sides:
(9 d)/28 = 90/49
Multiply both sides by 28/9:
Answer: d = 40/7
