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2 years ago

Tom converted the height this way 3 feet=1 yard

1 answer:

3 0

The units have to cancel out
1yard/3feet should be it
it is wrong since yards are bigger than feet so
379ft/1 times 1yd/3ft=379ydft/3ft=126.33333333yard

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Please help me with this question

Dmitrij [34]

Answer:

a) number 2 and 3 appeared a minimum number of times

b) number 5 appeared a maximum number of times

c) number 1, 4 and 6 appear an equal number of times (4 times). Also number 2 and 3 appear an equal number of times (1 time)

d) Even numbers turned up 9 times. The even numbers in a dice are 2 4 and 6. Add up how many times they came up: 1+4+4=9

f) Odd numbers turned up 11 times. The odd numbers in a dice are 1, 3 and 5. Add up how many times they came up: 4+1+6=11

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2 years ago

Find the volume and area for the objects shown and answer Question

klio [65]

Step-by-step explanation:

You must write formulas regarding the volume and surface area of the given solids.

$\bold{\#1\ Rectangular\ prism:}\\\\V=lwh\\SA=2lw+2lh+2wh=2(lw+lh+wh)\\\\\bold{\#2\ Cylinder:}\\\\V=\pi r^2h\\SA=2\pi r^2+2\pi rh=2\pir(r+h)\\\\\bold{\#3\ Sphere:}\\\\V=\dfrac{4}{3}\pi r^3\\SA=4\pi r^2$

$\bold{\#4\ Cone:}\\\\V=\dfrac{1}{3}\pi r^2h\\\\\text{we need calculate the length of a slant length}\ l\\\text{use the Pythagorean theorem:}\\\\l^2=r^2+h^2\to l=\sqrt{r^2+h^2}\\\\SA=\pi r^2+\pi rl=\pi r^2+\pi r\sqrt{r^2+h^2}=\pi r(r+\sqrt{r^2+h^2})\\\\\bold{\#5\ Rectangular\ Pyramid:}\\\\V=\dfrac{1}{3}lwh\\\\$

$\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}$

$\\\\h_2^2=\left(\dfrac{w}{2}\right)^2+h^2\to h_2=\sqrt{\left(\dfrac{w}{2}\right)^2+h^2}=\sqrt{\dfrac{w^2}{4}+h^2}=\sqrt{\dfrac{w^2}{4}+\dfrac{4h^2}{4}}\\\\h_2=\sqrt{\dfrac{w^2+4h^2}{4}}=\dfrac{\sqrt{w^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{w^2+4h^2}}{2}$

$SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}$

6 0

2 years ago

The Larger of two numbers is 27 more than the smaller. When added together , the sum of the larger number and five times the sma

Genrish500 [490]

Answer:

Small no. is 15

Larger no. is 15 + 27 = 42

Step-by-step explanation:

Let the small no. be x

Larger no. will be x + 27

5x + x + 27 = 117

6x + 27 = 117

6x = 117-27

x = 90/6

x = 15

4 0

2 years ago

Hey bro's help me!!

Vikentia [17]

Answer:

3x+10

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A spherical balloon was inflated such that it had a diameter of 24 centimeters. Additional helium was then added to the balloon

DanielleElmas [232]

To solve this we are going to use the formula for the volume of a sphere: $V= \frac{4}{3} \pi r^3$
where
$r$ is the radius of the sphere

Remember that the radius of a sphere is half its diameter; since the first radius of our sphere is 24 cm, $r= \frac{24}{2} =12$ . Lets replace that in our formula:
$V= \frac{4}{3} \pi r^3$
$V= \frac{4}{3} \pi (12)^3$
$V=7238.23 cm^3$

Now, the second diameter of our sphere is 36, so its radius will be: $r= \frac{36}{2} =18$ . Lets replace that value in our formula one more time:
$V= \frac{4}{3} \pi r^3$
$V= \frac{4}{3} \pi (18)^3$
$V=24429.02$

To find the volume of the additional helium, we are going to subtract the volumes:
Volume of helium= $24429.02cm^3-7238.23cm^3=17190.79cm^3$

We can conclude that the volume of additional helium in the balloon is approximately <span>17,194 cm³.</span>

8 0

3 years ago