<span>Let the total hour of exam is 3hrs ie 180 minutes.( since answer required in minutes).
Let as assume maths questions be in x minutes.
Let the assume rest of the question is in y minutes.
Given that out of 320 qns 40 is maths qns.
therefore, maths qn is =40 and rest of qns is 280.
Also given the time of maths qns is twice of rest. They related in the following equation. ie x:y=2:1 ; x/y =2/1
ie x=2y
therefore 2x+y= 180 min ; ie 2(2y)+y= 180 ; y=36
therefore resolving for x = 2*36 = 72
time spent for maths qn is 2*x = 2* 72 =144min.
rest of maths question is 36 min.</span>
Answer:
thanks
Step-by-step explanation:
Let's use <em>j</em> to represent Jiri's age.
If Pamela is 6 years younger that Jiri, her age can be represented by <em>j - 6</em>.
Since the sum of their ages is 64, we can setup the equation j + (j - 6) = 64.
Simplifying on the left, we have 2j - 6 = 64.
Adding 6 to both sides, we have 2j = 70.
Dividing both sides by 2, we have j = 35.
So Jiri is 35 years old and Pamela is 6 years younger or 29 years old.
Answer:
About 159 weigh more than 165 g and about 159 g weigh less Than 135 g
Step-by-step explanation:
Given that :
Mean, μ = 150
Standard deviation, σ = 15
Using the Zscore formula :
Zscore = (x - μ) / σ
For x > 165
P(x > 165)
Z = (165 - 150) / 15
Z = 15 /15 = 1
P(Z > 1) = 0.15866 (Z probability calculator)
1000 * 0.15866 = 158.66 = 159
For x < 135
P(x < 135)
Z = (135 - 150) / 15
Z = - 15 /15 = - 1
P(Z > - 1) = 0.15866 (Z probability calculator)
1000 * 0.15866 = 158.66 = 159