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LekaFEV [45]
3 years ago
10

Determine the maximum number of zeros. Then, determine the x-intercepts of the function. x^3-3x^2-22x+24

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

Three zeros x=-4,\ x=1,\ x=6

x-intercepts: (-4,0), (1,0), (6,0)

Step-by-step explanation:

Plot the graph of the function y=x^3-3x^2-22x+24 on the coordinate plane. This graph intersects the x-axis at three different points (see attached diagram):

  • (-4,0);
  • (1,0);
  • (6,0).

This means x=-4,\ x=1,\ x=6 are zeros of the function y=x^3-3x^2-22x+24

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Kaylis [27]

Answer:

y =47.5.

Step-by-step explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

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18y -36 - 252 = 14y - 98

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