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3 years ago

13+(-19)= Integer's Best one is mark as brainlist

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

Answer:

-6

Step-by-step explanation:

13+(-19) (distribute "+" sign into parentheses)

= 13-19

= -6

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HELP ME WITH ALL OF THESE ASAP i will give BRAINEST

lana66690 [7]

Answer:

The first is true.

8 · 21 = 168

The second is false.

The third is false.

The fourth is true.

Step-by-step explanation:

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3 years ago

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Find the inverse of the function. Show work. <br> g(x)= - 3/x-2 +2

4vir4ik [10]

Answer:

$\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}$

Step-by-step explanation:

We are given the function:

$\displaystyle g(x)=-\frac{3}{x-2}+2$

Let's find the inverse of g.

Call y=g(x):

$\displaystyle y=-\frac{3}{x-2}+2$

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

$y(x-2)=-3+2(x-2)$

Operate:

$yx-2y=-3+2x-4$

Collect the x's to the left side and the rest to the right side of the equation:

$yx-2x=-3-4+2y$

Factor the left side and operate on the right side:

$x(y-2)=-7+2y$

Solve for x:

$\displaystyle x=\frac{-7+2y}{y-2}$

Interchange variables:

$\displaystyle y=\frac{-7+2x}{x-2}$

Call y as the inverse function:

$\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}$

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3 years ago

A hotel gift shop ordered 30 T-shirts at $9.83 each, 90 hats at $4.49 each, and 10 beach towels at $5.27 each. What was the tota

IRINA_888 [86]

Answer:

Wow lol thats a lot of things also

Step-by-step explanation:

the answer is 768 dollars and 88 cents this is correct :)

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2 years ago

Find the remainder when f(x) is divided by (x - k).

liubo4ka [24]

Answer:

354

Step-by-step explanation:

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3 years ago

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"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d

dem82 [27]

Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is $\frac{1}{6} = 0.167$

There are 10 throws, so $n = 10$ .

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$ .

In which

$P(X < 2) = P(X = 0) + P(X = 1)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609$

$P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834$ .

Finally:

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161$ .

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

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3 years ago