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Viktor [21]
3 years ago
6

4.66666666667 as a fraction. (They all put 466666666667/100000000000)

Mathematics
2 answers:
natali 33 [55]3 years ago
7 0
<h2>Answer:</h2><h2><em><u>Brainliest plz</u></em></h2>

Step-by-step explanation:

that is because you have to write it like this:

4.666...

in fractions its 4 and 2/3

or

4 \frac{2}{3}

Naddika [18.5K]3 years ago
4 0

Answer:

14/3

Step-by-step explanation:

4.66666666667

0.66666666667=2/3

4\frac{2}{3}

14/3

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Hence x is 7 seconds

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Lena [83]

It would be Felix:

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Please really need the correct answer for this or I'll fail algebra 3
trapecia [35]

Answer:

4\pi

Step-by-step explanation:

S = Arc Lenth

θ = Radians

R = Radius

S = θR

So, now that we understand the formula, we will convert 72° into radians by introducing the equation x*\frac{\pi }{180}, x = 72

S =  72*\frac{\pi }{180} * R

given that R = 10

S = \frac{72*10*\pi }{180}

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2 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
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3 years ago
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22/4 cups. 1/2 times 2 is 1 cup. 11/4 times 2 is 22/4
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