Answer:
Step-by-step explanation:
This problem is just really long- it's trying to confuse you with complicated wording. Here's it demystified:
a)
t = 0 degrees Celsius
d = 1500 meters
Find the temperature, T.
b)
d = 300 meters
T = 26 degrees Celsius
Find the ground temperature, t.
NOTE: The temperatures are different! T is the final temperature and t is the ground temperature.
Answer:
x₁ > x₂
Step-by-step explanation:
Both actions imply a parable trajectories, since both are projectile shot cases.
Let´s call x₁ maximum distance in the first case
The maximum height is just in the middle of the curve, therefore x₁ the maximum horizontal distance is equal to 60 feet.
In the second case, the parable curve is modeled by:
y = x₂*( 0.08 - 0.002x₂) or y = 0.08*x₂ - 0.002*x₂²
A second degree equation, solving for x₂ and dismissing the value x₂ = 0
we get:
y = 0 ⇒ x₂*( 0.08 - 0.002x₂) = 0 x₂ = 0
And 0,08 - 0.002*x₂ = 0
- 0.002*x₂ = - 0.08
x₂ = 0.08/0.002
x₂ = 40 f
Then x₁ > x₂
Answer:
112 m^2
Step-by-step explanation:
A = b * h
b = 9 + 5 = 14 m
h = 8 m
So
A = 14 x 8 = 112 m^2
Answer:
What
Step-by-step explanation:
Answer: 105 miles?
I am not sure but that"s what I got
Step-by-step explanation:
