What is the coordinates of the vertex of y+10=4(x-1)^2
1 answer:
Answer:
(1, -10)
Step-by-step explanation:
Only the y can be on the left hand side. The square has been completed so all you need do is transfer the 10 to the right and read the x,y values for the vertex.
I have provided a graph to show you that the vertex and my answer are the same (hopefully).
y + 10 = 4(x - 1)^2 Subtract 10 from both sides.
y + 10-10=4(x -1)^2 -10 Combine
y = 4(x - 1)^2 - 10
Now we need to make the square term = 0
x - 1 = 0 Add 1 to both sides
x - 1 + 1 = 0 +1 Combine
x = 1 When x = 1 the square term will equal 0.
The vertex should be (1, - 10)
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The probability is 0.006, or 0.6%.
This is binomial; there are a fixed number of trials (10), the events are independent (the chances of one occurring do not affect the chances of the other occurring), and there are two outcomes (either right or wrong).
He must get 6 of the 10 questions correct, so k is 6 and n is 10. The probability of getting a question correct is 1/5=0.2; the probability of getting a question incorrect is 4/5=0.8.
This is binomial; there are a fixed number of trials (10), the events are independent (the chances of one occurring do not affect the chances of the other occurring), and there are two outcomes (either right or wrong).
He must get 6 of the 10 questions correct, so k is 6 and n is 10. The probability of getting a question correct is 1/5=0.2; the probability of getting a question incorrect is 4/5=0.8.
The solution is in the attached below
Circumference=31.4yd
