Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
Hence, this is the required solution.
Hello :D
To work this out you need to round the numbers to a whole number.
19.9 = 20
5.8 = 6
20 x 6 ≈ 120
I hope this helps :)
Answer:
The domain of a function is defined as the set of x-values for which the function is real and defined. The first alternative is correct
Step-by-step explanation:
Answer: x = 4.5
Step-by-step explanation:
1) Reorder the terms:
3x = -9 + 5x
2) Solving
3x = -9 + 5x
3) Solving for variable 'x'.
4) Move all terms containing x to the left, all other terms to the right.
5) Add '-5x' to each side of the equation.
3x + -5x = -9 + 5x + -5x
6) Combine like terms: 3x + -5x = -2x
-2x = -9 + 5x + -5x
7) Combine like terms: 5x + -5x = 0
-2x = -9 + 0
-2x = -9
8) Divide each side by '-2'.
x = 4.5
9) Simplifying
x = 4.5
Answer:
1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 hope it help jk dont do this i have no clue
Step-by-step explanation:
10000000000000o0000000000000000000000000000000000000000ooooooooooooooooooooooooooo0000oooo00o0o0o0oo00oooooooo0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000ooooooooooooooooooooooooooooooooooooooo
