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gayaneshka [121]
3 years ago
8

PLEASE HELP ASAP!! WILL MARK BRAINLIEST!!!!

Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

A, 23.2

Step-by-step explanation:

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3 hours 20 minutes - 1 hour 48 minuets <br> A. 2.12<br> B. 2.52<br> C. 1.32<br> D. 1.53
chubhunter [2.5K]
3 hours and 20 minutes minus 1 hour and 48 minuets equals an hour and 32 minutes. There are 60 minuets in an hour and 60 divided by 32 is 0.53. This means that your final answer is:
D. 1.53
5 0
3 years ago
Sahana sells two products for ₹. 8000 each gaining 8% on one and losing 6% on the other. Find her gain or loss percent in the wh
Margaret [11]

Based on the information given the gain or loss percent on the whole transaction​ is 1%.

<h3>Gain or loss percent: </h3>

First step is to calculate the profit on the whole transaction

Profit=(8%×8,000)-(6%×8,000)

Profit=$640-$480

Profit=$160

Now let calculate the gain or loss percentage on the whole transaction

Gain or loss percentage=160/(8000+8000)×100

Gain or loss percentage=160/16000×100

Gain or loss percentage=1%

Inconclusion the gain or loss percent on the whole transaction​ is 1%.

Learn more about gain or loss here:brainly.com/question/25278228

5 0
2 years ago
How would you graph the solution set of x/1 ≤ -18?
Korolek [52]

Get a graphing calculator

4 0
3 years ago
Read 2 more answers
What is the value of x?
musickatia [10]
X = 7. Because both lines equal the same so it has to equal 75
11 x 7 = 77
77-2 = 75
X = 7
6 0
2 years ago
Read 2 more answers
Please help me. these problems<br>​
jeyben [28]

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Step-by-step explanation:

You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

3 0
3 years ago
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