Question

Raphael paid $656 for a camera during a 20% off sale. What was the camera's regular price? Please work the problem and show your work so I can understand it better.

Answer 1

$\large\begin{array}{l}\textsf{During the sale, the camera was being sold with a}\\\textsf{discount of }\mathsf{20\%}\textsf{ over it's original price:}\\\\ \bullet~~\textsf{original price: x;}\\\\ \bullet~~\textsf{price during the sale:}\\\\ \mathsf{x-20\%\,x=656}\\\\ \mathsf{(1-20\%)x=656}\\\\ \mathsf{(1-0.20)x=656}\\\\ \mathsf{0.80x=656}\\\\ \mathsf{x=\dfrac{666}{0.80}}\\\\ \begin{array}{lcl} \boxed{\begin{array}{c}\mathsf{x=\ ~820} \end{array}}&\longleftarrow&\textsf{this is the camera's}\\ &&\textsf{regular price.} \end{array} \end{array}$


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Tags: percentual discount off sale regular price

Answer 2

The answer is $820.
I found this by 0.8x = 656
(Remember, a 20% discount means that it costs 80%, or 0.8, of the original price)
Then, divide 0.8 on both sides:
0.8x/0.8 = 656/0.8
This leaves you with:
x = 820