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Serggg [28]
4 years ago
5

The region enclosed by the semicircle is revolved completely around the x-axis. A. Describe the solid of revolution that is form

ed b. Find its volume in terms of pi.
Mathematics
1 answer:
tester [92]4 years ago
7 0

Answer:

The volume of this sphere = \frac{4}{3}\times \pi r^{3}

Step-by-step explanation:

The region enclosed by the semicircle is revolved completely around the x-axis . Then the solid formed is a sphere of the same radius as that of the semicircle. We have to find the volume of this sphere. If the semicircle had center at the origin then the sphere also has the center at the origin.

Let the radius of given circle = r

Surface area of this sphere = 4\pi r^{2}

The volume of this sphere = \frac{4}{3}\pi\times r^{3}

This is the volume of the required solid.

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Marta_Voda [28]

Answer:

77

Step-by-step explanation:

6 0
3 years ago
-4y - 20 +19= -y + 17
Anestetic [448]

Answer:

y= -6

Step-by-step explanation:

<u>-4y - 20 + 19 = -y + 17</u>        *add y on the right to get rid of -y

+y                    +y                then add it to -4y

<u>-3y - 20 + 19 = 17</u>               *add 20 to the left to get rid of -20  

     +20           +20              then add it to 17

<u>-3y + 19 = 37</u>                      *subtract 19 from the left to get rid of 19

       -19    -19                      then subtrcat 19 from 37 as well

<u>-3y</u> = <u>18</u>                             *now we want to divide both sides by -3 to

-3      -3                               get y by it's self

y = -6                                *no we're left with y = -6 :D

- im sorry if this doesn't make sense x(

5 0
3 years ago
Help please due in 10 min
Oksanka [162]

Answer:

function M and P have the same rate of change

8 0
3 years ago
What value of x is in the solution set of 2x – 3 &gt; 11 – 5x?
Allisa [31]

Answer:

answers are below

4 0
3 years ago
Aaron creates a stacked cake comprised of three cylindrical sections and plans to cover the top of each section with a different
spin [16.1K]

Answer:

Option C

Step-by-step explanation:

Complete question is

Each lower section is a total of two inches wider than the section above it. If the yellow top of the upper section has an area of 12.56 square inches, what is the approximate area of the green visible portion of the bottom section which he will need to cover with icing?

A. 13 square inches

B. 88 square inches

C. 49 square inches

D. 22 square inches

Solution -

Given

Top of each cylindrical section is covered with a different color icing

Radius of each color icing is two inches less than the section below it.

Let the radius of the icing be "r"

Then the surface area of the icing will be  \pi r^2

Now area of the yellow icing is equal to 12.56 square inches

Thus,

\pi r^{2}  = 12.56

On solving the above equation for r, we get -

r^2 = \frac{12.56}{3.14} \\r^2 = 4\\r = \sqrt{4} \\

r = 2 inches

Now radius of the section below the icing is equal to

r + 2\\= 2+ 2\\

= 4 inches

Area of the section below the icing

= \pi r^2\\= 3.14 * 4^2\\= 50.24

Thus, option C is correct

4 0
4 years ago
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