Help me with number 1 pleaseeeee !!!!!!

At the start of a science experiment, the temperature is 10 degrees Celsius. If the temperature decreases by a constant rate of

notka56 [123]

Answer:

-5 If it is one of your answers it will be -5

Step-by-step explanation:

If you take 10 and have 3 decrease every minute and did it for 5 minutes it will go 10 7 4 1 -2 -5 That is 5 minutes of the temperature decreasing by 3 I hope it is right.

3 0

3 years ago

Find the distance between the points (1, 7) and (10, 1) Please help:)

klio [65]

Answer:

The distance between the points (1, 7) and (10, 1) is 10.82 units

Step-by-step explanation:

Distance between two points

The distance between points A(x,y) B(w,z) can be calculated with the formula:

$d=\sqrt{(z-y)^2+(w-x)^2}$

We are given the points (1,7) and (10,1), let's use their values and compute the required distance:

$d=\sqrt{(1-7)^2+(10-1)^2}$

$d=\sqrt{(-6)^2+(9)^2}$

$d=\sqrt{36+81}=\sqrt{117}\approx 10.82$

The distance between the points (1, 7) and (10, 1) is 10.82 units

7 0

3 years ago

spin [16.1K]

Answer:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

$\hat p=\frac{18}{100}=0.18$ estimated proportion of ounce cups of coffee that were underfilled

$p_o=0.1$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:

Null hypothesis: $p\leq 0.1$

Alternative hypothesis: $p > 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed for this case is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a one right tailed test the p value would be:

$p_v =P(Z>2.67)=0.0037$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .