Find the sum [3n+1 OP 252 246 234

loris [4]

Answer:

25i

Step-by-step explanation:

Your calculator or your knowledge of powers of 5 will tell you that √625 is 25. The minus sign makes the root imaginary.

$\sqrt{-625}=\sqrt{(-1)(25^2)}=25\sqrt{-1}=25i$

6 0

4 years ago

Read 2 more answers

Would like to know how to do this problem.

bogdanovich [222]

well it would be very helpful thank you

8 0

3 years ago

What is the GCF of the polynomials terms? 14a^3b^4-7ab^7+21a^2b

cupoosta [38]

Answer:

$\large\boxed{7ab}$

Step-by-step explanation:

$14a^3b^4-7ab^7+21a^2b\\\\14a^3b^4=2\cdot\boxed7\cdot\boxed{a}\cdot\boxed{b}\cdot b\cdot b\cdot b\\\\7ab^7=\boxed7\cdot\boxed{a}\cdot\boxed{b}\cdot b\cdot b\cdot b\cdot b\cdot b\cdot b\\\\21a^2b=3\cdot\boxed7\cdot\boxed{a}\cdot a\cdot\boxed{b}\\\\GCF(14a^3b^4,\ -7ab^7,\ 21a^2b)=\boxed7\cdot\boxed{a}\cdot\boxed{b}=7ab$

5 0

3 years ago

An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color

alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁ B₂B₁ W₁B₁ W₂B₁ W₃B₁

B₁B₂ B₂B₂ W₁B₂ W₂B₂ W₃B₂

B₁W₁ B₂W₁ W₁W₁ W₂W₁ W₃W₁

B₁W₂ B₂W₂ W₁W₂ W₂W₂ W₃W₂

B₁W₃ B₂W₃ W₁W₃ W₂W₃ W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

$P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40$

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

$P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36$

Thus, the probability that only white balls are drawn is 0.36.

4 0

3 years ago

Question

Zinaida [17]

Answer:

$\frac{x}{5}-6=15$

(addition property of equality)

$\frac{x}{5}=21$

(multiplication property of equality)

$x=105$

Step-by-step explanation:

Given:

$\frac{x}{5}-6=15\\\frac{x}{5}=21\\x=105$

To find: appropriate properties to justify each step

Solution:

According to division property of equality, if both sides of an equation are divided by the same nonzero number, the sides remain equal.

According to multiplication property of equality, if both sides of an equation are multiplied by the same nonzero number, the sides remain equal.

According to addition property of equality, if same number is added to both sides of an equation, the sides remain equal.

According to subtraction property of equality, if same number is from both both sides of an equation, the sides remain equal.

$\frac{x}{5}-6=15$

Add 6 to both sides ( addition property of equality )

$\frac{x}{5}-6+6=15+6\\\\\frac{x}{5}=21$

Multiply both sides by 5 (multiplication property of equality)

$\frac{x}{5}=21\\\frac{x}{5}(5)=21(5)\\ x=105$

3 0

3 years ago