solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
The correct answer is - 768.
Step-by-step explanation:
The given question is based on a specific pattern present in between the numbers in the given series -
Series = 25 50 99 196 388
to find - next number in series
let us find the relation between the initial two number:
25 - 50, here number 50 is two times of 25 or (x*2-0)
relation between 2nd and 3rd number:
50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)
relation between 3rd and 4th number:
99 - 196, here 196 is two times of 99 minus 2 or (x*2-2)
relation between 4th and 5th number:
196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)
So on this pattern, the next number would be = x*2-8
388*2-8
= 768
Percent of decrease :
Original - New / Original
so...
80 - 52 / 80 ---->
28/80
.35 multiply by 100 to get percent
35% increase Hope I helped if you have any questions let me know! :)
If you would like to know how many hours did Judd work outside, you can calculate this using the following steps:
40 hours
outside: 7/10 of the hours = 7/10 * 40 hours = 7/10 * 40 = 28 hours
Judd worked 28 hours outside.
