A coin is tossed 6 times. Find the probability P(of exactly 4 occurrences of heads).
1 answer:
Let's draw!
H 1 T
HT 2 HT
HTHT 3 HTHT
HTHTHT 4 HTHTHT
HTHTHTHT 5 HTHTHTHT
HTHTHTHTHT 6 HTHTHTHTHT
You can count the probabilities using this.
HHHHTT
HHHTHT
HHTHHT
HHTHTH
HHHTTH
HTHHHT
HTTHHH
HTHTHH
HTHHTH
THHHHT
THHHTH
THHTHH
THTHHH
TTHHHH
Therefore, I think the probability is 14/64. Not sure so check my work.
14 combinations
64 outcomes (2+4+8+16+32+64 or 2^n)
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Answer:
n = 11
Step-by-step explanation:
n+ 1 = 4(n-8)
<=> n + 1 = 4n - 4×8
<=> 4n - n = 1 + 4×8
<=> 3n = 33
<=> n = 11
