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antiseptic1488 [7]
3 years ago
12

A coin is tossed 6 times. Find the probability P(of exactly 4 occurrences of heads).

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0
Let's draw!

H                             1                              T
HT                           2                           HT
HTHT                      3                      HTHT
HTHTHT                 4                  HTHTHT
HTHTHTHT            5             HTHTHTHT
HTHTHTHTHT       6        HTHTHTHTHT

You can count the probabilities using this.

HHHHTT
HHHTHT
HHTHHT
HHTHTH
HHHTTH
HTHHHT
HTTHHH
HTHTHH
HTHHTH

THHHHT
THHHTH
THHTHH
THTHHH
TTHHHH

Therefore, I think the probability is 14/64. Not sure so check my work.
14 combinations
64 outcomes (2+4+8+16+32+64 or 2^n)

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(a) 3 - 2/3÷4/3 × 7<br>(b) [(2/3)/(5/6)]-2/5<br>(c) {(-3/4) +( 1/2)}/{(2/5)-(5/2)}<br>​
BartSMP [9]

Step-by-step explanation:

a. (3 - 2/3) ÷ (4/3 x 7)

= [(3 x 3) / (1 x 3) - 2/3] ÷ 28/3

= (9/3 - 2/3) ÷ 28/3

= 7/3 x 3/28

= 21/84

= (21 x 1) / (21 x 4)

= 1/4

b. 2/3 ÷ 5/6 - 2/5

= 2/3 x 6/5 - 2/5

= 12/15 - 2/5

= (3 x 4) / (3 x 5) - 2/5

= 4/5 - 2/5

= 2/5

c. (- 3/4 + 1/2) ÷ (2/5 - 5/2)

= [- 3/4 + (1 x 12) / (2 x 2)] ÷ [(2 x 2) / (5 x 2) - (5 x 5) / (2 x 5)]

= (- 3/4 + 12/4) ÷ (4/10 - 25/10)

= 9/4 ÷ (- 21/10)

= 9/4 x - 10/21

= - 90/84

= (6 x - 15) / (6 x 14)

= - 15/14.

If you have any doubt, then you can ask me in the comments.

6 0
3 years ago
Read 2 more answers
A breathalyser test is used by police in an area to determine whether a driver has an excess of alcohol in their blood. The devi
Xelga [282]

Answer: 1)The drivers with low alcohol in take from the breathlyser, being above the limit, A = 5/100;

2)The drivers above the alcohol limit, give reading below that level, B = 15/100;

3) The drivers above the alcohol limit that are arrested at radom by police, C = 12/100

Step-by-step explanation: a)  A + B + C = 5/100 + 15/100 + 12/100 = 32/100

b) 1 - ( A + B + C) = 1 - 32/100 = 68/100

c) A = 5/100

d) 1 - 5/100 = 95/100

3 0
3 years ago
Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4
Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of  (-9,-8) and (7,-4)

midpoint formula is

\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}

\frac{-9+7}{2} ,\frac{-8+-4}{2}

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}

slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4  and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10


3 0
3 years ago
Answer fast!!!!!!!!!!!!!!!!!!!!!!!!!!
Veronika [31]

Answer:

Choice b.

Step-by-step explanation:

170 is a little more than half of 330  so that's the onee.

7 0
3 years ago
For what value of x is sin x = cos 19°, where 0°&lt; x &lt; 90°? 38°
Digiron [165]
Sin x =cos 19 X =sin^1(cos 19) X=71
6 0
3 years ago
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