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3 years ago

12

How do you calculate x, y and z?

1 answer:

bixtya [17]3 years ago

3 0

The inscribed angle theorem says that the central angle in each of these cases is twice as large as the inscribed angle. So $x=70^\circ$ , $y=85^\circ$ , and $z=90^\circ$ .

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Find<br> the<br> Inverse<br> y = x+10/7

Alona [7]

Answer:

x - $\frac{10}{7}$

Step-by-step explanation:

y = x + 10/7

x = y + 10/7

x = y + 10/7

x - 10/7 = y

y = x - 10/7

x - $\frac{10}{7}$

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4 years ago

A computer downloads a movie at a constant rate

Doss [256]

It is usually in Meaga Bytes per second.

MB/s depending on the speed of your Internet.

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3 years ago

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A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

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3 years ago

when planning for a party one caterer recommends the amount or meat be at least 2 pounds less than 1/3 the total number of guest

IgorLugansk [536]

Answer:

Let x be the number of guest and y be the quantity of meat,

According to the question,

$y\geq \frac{x}{3}-2$

Since, the related equation of the above inequality,

$y=\frac{x}{3}-2$

Having x-intercept = (6,0),

y-intercept = (0,-2)

Also,'≥' shows the solid line,

Now, 0 ≥ 0/3 - 2 ( true )

Hence, the shaded region of above inequality will contain the origin,

Therefore, by the above information we can plot the graph of the inequality ( shown below ).

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3 years ago

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6. A publisher requires 2⁄3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the near

earnstyle [38]

We have (2/3)÷5 = 2/15 advertisments for 1 page;

Then, we have 98 · (2/15) = 12.2(6) advertisments for 98 pages;

The nearest whole page is 12.

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4 years ago