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3 years ago

Please help me right away! will give brainliest

Mathematics

1 answer:

Anon25 [30]3 years ago

4 0

The table represents a greater unit rate of change.

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Mary ran 3.45 miles on Monday, 2.2 miles on Tuesday, 0.055 miles on Wednesday, and 9.03 miles on Thursday. How many total miles

Nata [24]

Well all you need to do is add them so 3.45 + 2.2 = 5.65 then add 0.055 to 5.65 which is 5.705 and last but not least, add 9.03 to 5.705 which is 14.735 which makes 14.735 how many miles she ran. Hope this helps

4 0

2 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

Which pair of angles shares Ray AG as a common side

Anastaziya [24]

BAF and FAD is the answer

4 0

3 years ago

The weight of an elephant is 10^3 times the weight of a cat. If the elephant weighs 14,000 pounds,how many pounds does the cat w

Ket [755]

Answer:

14 pounds.

Step-by-step explanation:

10 cubed is 1000.

14000/1000=14

6 0

2 years ago

Please someone help me

Dovator [93]

m=69 miles

you can find this because if you divide the 9 by 6 as they are matching sides you get 1.5, take that number and multiply it by the 46 and get the 69! hope that helps :D

5 0

2 years ago