Answer:
RS = 2
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
RS² + RT² = TS² , that is
RS² + 6² = 8²
RS² + 36 = 64 ( subtract 36 from both sides )
RS² = 28 ( take the square root of both sides )
RS = 
= 
= 2 ≈ 5.3 ( to 1 dec. place )
Answer:
i think it A
Step-by-step explanation:
Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)
Answer: k = -5
explanation-
distribute: -3k + -21 - 5k + 4= 23
combine: -8k -17 = 23
add 17 to both sides: -8k = 40
divide both sides by -8: k=-5
