Poster because if you have that much space....well what I do is calculate it by the centimeters in square divide:)
Answer:
The five factors to consider when trying to choose between a Solid State Drive, a Hard Disk Drive and, an External Hard Disk Drive are:
- Read/Write Speed
- Weight
- Power Consumption
- Cost
- Storage Capacity
- Solid State Drives (SSDs) are typically lighter in weight, faster and do not consume much power.
- Hard Disk Drives are relatively cheaper than SSDs. They also come with higher storage capacities but are more power-hungry and slower because they rely on mechanical/moving parts to read and write data.
- External HDDs are the cheapest of the three. They are not internal which is a major drawback given the additional weight. However, they come with gargantuan storage capacities that make you want to rethink having one. Besides, unlike SSDs, you can easily get them in computer accessories shops offline or online.
Cheers!
use an anchor tag(<a>This is an anchor tag</a>) and use the href attribute and set it's destination to the section element who's id or class is "sisters".
Example:
<a href="#Sisters">Click Here!</a>
then you can add this somewhere on the document.
<section id="Sisters">Hello World!</section>
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
B. forum
they hold the most accurate information and people respond the most
