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Akimi4 [234]
3 years ago
10

José has 10 times as many baseball cards as Suki. Suki has 5 cards. Let n be the number of cards José has.

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

5 x 10 = n

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
6 0

Answer:

OB or OD        

Step-by-step explanation:

You might be interested in
The solution system to 3y-2x=-9 and y=-2x+5
Alecsey [184]

Answer:

\boxed{(3,-1)}

Step-by-step explanation:

<em>Hey there!</em>

<em />

Well to find the solution the the given system,

3y - 2x = -9

y = -2x + 5

So to find x lets plug in -2x + 5 for y in 3y - 2x = -9.

3(-2x + 5) - 2x = -9

Distribute

-6x + 15 - 2x = -9

-8x + 15 = -9

-15 to both sides

-8x = -24

Divide -8 to both sides

<u>x = 3</u>

<u />

Now that we have x which is 3, we can plug in 3 for x in y = -2x + 5.

y = -2(3) + 5

y = -6 + 5

<u>y = -1</u>

<u><em /></u>

So the solution is (3,-1).

<em />

<em>Hope this helps :)</em>

4 0
3 years ago
Answer this and ill give brainliest
nekit [7.7K]

Answer:

-4.65< -4 and 2/5

Step-by-step explanation:

To solve, this we can convert the fraction -4 and 2/5 into a decimal so that the values can be more easily compared. When we do this, we get the result that -4 and 2/5 equals -4.4. Now we can clearly see which value is greater because they are written in the same form:

-4.65<-4.4

-4.65<-4 2/5

6 0
2 years ago
Read 2 more answers
Mr. Dumond bought a 5-liter jug of water for a family cookout. He used liters filling water cups for guests. A while later, he u
hammer [34]

Answer:

what is the question need more decription

4 0
2 years ago
Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

SE= Standard error.

Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

Hence, the required confidence interval : (13.4996, 32.5004)

8 0
2 years ago
Given square PQRS, determine the missing information.
Julli [10]

Answer:

jb

Step-by-step explanation:

4 0
2 years ago
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