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2 years ago

What is the answer pls it’s for a grade

Mathematics

1 answer:

Licemer1 [7]2 years ago

6 0

The answer
2
Explanation
The median is the middle number and if you take off one side from the left and one side from the right until you have your middle number

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The temperature at 6 am today was T. Yesterday

Paladinen [302]

Answer:

T-X

Step-by-step explanation:

Today=T

Yesterday = X

To find the diffrence you need to subtract Today from Yesterday then you will get your answer

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2 years ago

5 3/5 as a mixed number

Andrej [43]

5 3/5 is a mixed number but the improper fraction would be 18/5

8 0

1 year ago

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HELP ME AGAIN I MIGHT PASS

trapecia [35]

Answer:

x=70

Step-by-step explanation:

it's 70 because 50 and 20 is proportional to x

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2 years ago

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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

49 more than the quotient of an unknown number and 12 is 53. What is the value of the unknown number?

nalin [4]

The unknown number is 48 using the equation: x ÷ 12 +49=53 subtract 49 from both sides and get x ÷ 12 = 4 multiplying by 12 on both side to get rid of the ÷12 and get the final answer of x=48.

6 0

3 years ago