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4 years ago

How do you do this problem 3x times x squared

Mathematics

2 answers:

Alisiya [41]4 years ago

8 0

3x^2
3x times x is 3x, and squared which is basically doubled.

kobusy [5.1K]4 years ago

5 0

both variables are x

pretend there is an imaginary 1 in front of the x for x squared

3 x 1 = 3

x^2 x X = x^3

this is because when multiplying numbers with the same variable like this problem for instance then you add the squared (2) with the x ( imaginary 1)

so 3x^3 is the answer

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Answer:

Customers who have not started picking berries

Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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4 years ago

What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

frosja888 [35]

Complete Question:

The given line segment has a midpoint at (3, 1). On a coordinate plane, a line goes through (2, 4), (3, 1), and (4, -2).

What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

Answer:

$y = \frac{1}{3}x$

Step-by-step explanation:

From the question, we understand that the line goes through $(2, 4), (3, 1), and\ (4, -2).$

First, we calculate the slope of the above points

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$(x_1,y_1) = (2,4)$

$(x_2,y_2) = (3,1)$

$m = \frac{1 - 4}{3 - 2}$

$m = \frac{-3}{1}$

$m = -3$

Also; from the question, we understand that the line segment is perpendicular to the above points.

This slope (m2) of the line segment is calculated as:

$m_2 = -\frac{1}{m}$

Substitute -3 for m

$m_2 = -\frac{1}{-3}$

$m_2 = \frac{1}{3}$

Lastly, we calculate the equation of the line using:

$y - y_1 = m_2(x - x_1)$

The line segment has a midpoint at (3, 1)

So:

$y - 1 = \frac{1}{3}(x - 3)$

Open bracket

$y - 1 = \frac{1}{3}x - 1$

Add 1 to both sides

$y - 1 +1= \frac{1}{3}x - 1+1$

$y = \frac{1}{3}x$

Hence, the equation of the line segment is: $y = \frac{1}{3}x$

7 0

3 years ago

Read 2 more answers

what key feature(s) can be easily identified from standard form? Explain how each key feature is related to the rollercoaster. U

raketka [301]

Answer:

Step-by-step explanation:

Key features

when t = 0

the initial height is 143/3 = 47⅔ ft

initial velocity is -310/3 = -103⅓ ft/s (downward)

initial acceleration is 2(64) = 128 ft/s² (upward)

I would not like to ride this roller coaster!

that's about four times the acceleration of gravity, and it only increases as the car gets to the bottom of the curve at t = 1 s

For part 3

I'm not sure what they mean by "not realistic"

while the initial acceleration is high. the acceleration at t = 1 is zero except that in 'reality' the car would have to be going through a curve to change direction from down to up. That would create very high centripetal acceleration and therefore centripetal forces.

5 0

2 years ago