Answer: three sets of value show 3 consecutive increases and they could be the intensities during fourth, fifth, and six visits:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Explanation:
1) The program recommends a constant intensity for 3 visits, which is what the table shows:
Day Intensisty
1 63%
2 equal ⇒ 63%
3 equal ⇒ 63%
2) Hence, you have to determine the valid sets that meet the recommendation for the fourth, fifth, and six visits, which are the next three.
2) For the next three visits, the program recommensd increasing intensities.
There are three options that show 3 consecutive increases; they are:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Therefore, those are the choices that apply.
ok so F (0) should be equaled to = 0
Answer:
The largest possible value of n is 11.
(A) is correct option.
Step-by-step explanation:
Given that,
The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.
We need to find the largest possible value of n
Using given data,
The smallest number of two digit is 10.
Now, we removed last digit then we get 1 which is equal to 10 divided 10.
So, n = 10
But the largest number of two digit is 99.
We removed last digit then we get 9 which is equal to 99 divided 11.
So, n = 11
Hence, The largest possible value of n is 11.
(A) is correct option.
The order of the 3 books does not matter so its the number of combinations of 3 from 45
b is the correct choice
Answer:
Hypotenuse= 10, short leg= 5
Step-by-step explanation:
