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3 years ago

Write four hundred thirty-six thousandths in standard form

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

Answer:

436,000

Step-by-step explanation:

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The area of a rectangle is (81x2 − 4y2) square units. Determine the dimensions of the rectangle by factoring the area expression

oksano4ka [1.4K]

Answer:

The dimension of the rectangle are $9\cdot x - 2\cdot y$ units and $9\cdot x + 2\cdot y$ units, respectively.

Step-by-step explanation:

Geometrically speaking, the area of a rectangle is equal to the product of its base and its height. If we know that area of the figure is $81\cdot x^{2} - 4\cdot y^{2}$ square units, then we proceed to factor the expression:

1) $A = 81\cdot x^{2} - 4\cdot y^{2}$ Given

2) $A = (9\cdot x -2\cdot y)\cdot (9\cdot x + 2\cdot y)$ $a^{2} - b^{2} = (a + b) \cdot (a - b)$ /Result

The dimension of the rectangle are $9\cdot x - 2\cdot y$ units and $9\cdot x + 2\cdot y$ units, respectively.

6 0

3 years ago

Suppose your marginal cost of making a peanut butter and jelly sandwich is constant at $10, but the marginal benefit of eating t

Softa [21]

Answer:

At most 3 sandwiches i would eat at this situation

Step-by-step explanation:

Making a first sandwich has a constant value 10$ but its marginal benefit is 12$. There is a 2$ benefit exist if i eat one.

Making the second one costs 20$ but its marginal benefit is 22$. Still 2$ benefit is exist if i eat the second one also.

Making the third one costs 30$ ant its marginal benefit also 30$. There is a even situation here. Making three sandwiches still an option.

After third one marginal benefit becomes lower than marginal cost of sandwiches.

5 0

4 years ago

Find the equation of the line that contains the given point and the given slope. Write the equation in slope-intercept form.

stealth61 [152]

The slope-point form of a line:

$y-y_0=m(x-x_0)$

The slope-intercept form of a line:

$y=mx+b$

$m=6,\ (4,\ 1)\to x_0=4,\ y_0=1$

Substitute

$y-1=6(x-4)\qquad|\text{use distributive property}\\\\y-1=6x-24\qquad|\text{add 1 to both sides}\\\\\boxed{y=6x-23}$

$m=-5,\ (6,\ -3)$

Substitute

$y-(-3)=-5(x-6)\qquad|\text{use distributive property}\\\\y+3=-5x+30\qquad|\text{subtract 5 from both sides}\\\\\boxed{y=-5x+24}$

$m=-\dfrac{1}{2},\ (-8,\ 2)\\\\y-2=-\dfrac{1}{2}(x-(-8))\\\\y-2=-\dfrac{1}{2}(x+8)\\\\y-2=-\dfrac{1}{2}x-4\qquad|\text{add 2 to both sides}\\\\\boxed{y=-\dfrac{1}{2}x-2}$