How do I rewrite 5log9x^7 in a form that doesn't use exponents? 5log9x^7 = [ ] log9x
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Hi there,
This is the original inequality equation:
So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.
Now, we multiply both sides by x + 1:
Then, we multiply both sides by x - 1:
Next, we subtract x² from both sides:
After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1 </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1 </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0 </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1 </span><span>(Works in original inequality)
Therefore, the answer to your query is -1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>
This is the original inequality equation:
So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.
Now, we multiply both sides by x + 1:
Then, we multiply both sides by x - 1:
Next, we subtract x² from both sides:
After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1 </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1 </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0 </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1 </span><span>(Works in original inequality)
Therefore, the answer to your query is -1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>