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saw5 [17]
3 years ago
11

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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the earth rotates about its axis once every 23 hours, 56 minutes and 4 seconds. Approximate the number of radians the earth rota
marishachu [46]

Answer:

\frac{\pi}{43082}\text{ radians per second}

Step-by-step explanation:

Given,

Time taken in one rotation of earth = 23 hours, 56 minutes and 4 seconds.

Since, 1 minute = 60 seconds and 1 hour = 3600 seconds,

⇒ Time taken in one rotation of earth = (23 × 3600 + 56 × 60 + 4) seconds

= 86164  seconds,

Now,  the number of radians in one rotation = 2π,

That is, 86164 seconds = 2π radians

\implies 1\text{ second }=\frac{2\pi}{86164}=\frac{\pi}{43082}\text{ radians}

Hence, the number of radians in one second is \frac{\pi}{43082}

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Answer:

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4 years ago
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snow_lady [41]
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