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saw5 [17]
3 years ago
11

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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Write an expression for the calculation add 3 and 8 and then multiply by 9
melisa1 [442]

Hey there!

Basically it wants you to add 3 and 8 from each other, what ever the answer to that part, you multiply the result by 9

Here this is what i meant

3 + 8 = 11 \\ 11 ( 9) = 99

Or you could do this method too!

(3 +8) (9) \\ \\ 3 + 8 = 11 \\ 11(9) \\ = 99

They both give you the result of 99

So, I am assuming your expression would look like this: (3 + 8) * 9

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
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kolbaska11 [484]

Answer:

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Step-by-step explanation:

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3 years ago
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sashaice [31]
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6 0
3 years ago
9th grade
il63 [147K]

Answer:

May be the second one

Step-by-step explanation:

hope it'll help ☺️

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