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saw5 [17]
3 years ago
11

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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What is the solution of the following system of equations?<br> 2x + y = -7<br> -3x - 2y = 10
pentagon [3]

Answer:

the solution is    (-4, -3)

Step-by-step explanation:

Multiply the first equation by 2.  This produces 4x + 2y = -14.

Now combine this result with the second equation:

4x + 2y = -14

-3x - 2y = 10

------------------

 x          = -4

Subbing -4 for x in the first equation yields 2x - 4 = -7, or 2x = -3.  

Then x = -3/2, and the solution is    (-4, -3)

8 0
3 years ago
Britney building dollhouse that was a scale model of her own house the dog House was 10 inches long while her actual house had a
defon

9514 1404 393

Answer:

  32 feet

Step-by-step explanation:

The width of the doll house is 8/10 of the length of the doll house, so the actual house will have a width that is 8/10 of its length:

  (8/10)(40 ft) = 32 ft

The actual house is 32 feet wide.

4 0
3 years ago
Select Parameter or Statistic to classify each statement.
Annette [7]

Answer:

1) Statistic

2) Parameter

3) Statistic

4) Parameter.

Step-by-step explanation:

Parameter: is a number that describes the whole population.

Statistic: is a number that describes a sample.

The difference is:

50% of the cats are nice (parameter, because talks about all the cats)

out of 100 cats surveyed, 39 are nice (statistic, because talks about a sample of 100 cats)

Then:

1) 85% of those surveyed were in favor of bike lanes.

This only refers to the surveyed people, so this only refers to a sample (and not the population that this sample represents) then this is a statistic statement.

2) Each member of the soccer team has an average of 2 jerseys.

In this case, we are talking about the whole population (the soccer team) then this is a parameter

3) Of the 100 swim teams surveyed across America, 23 practice 10 hours a week.

Here the information is about the sample (only 100 swim teams). So here the correct option is statistic.

4) The golf team's average score is 79

Here the information is about the average score for the entire golf team, so this information is about all the population in the golf team, then in this case the correct option is parameter.

7 0
3 years ago
Read 2 more answers
Help, adding extra text so that I can post this question
GREYUIT [131]
The answer 0.1, 0.136, 0.652, 0.87
8 0
3 years ago
Read 2 more answers
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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