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saw5 [17]
3 years ago
11

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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if f(1) = -5 and f(n) = f(n-1) +7, find the first four terms and the common difference of the sequence
Alex_Xolod [135]

Answer:

- 5, 2, 9, 16 and d = + 7

Step-by-step explanation:

to obtain the first four terms substitute n = 2, 3, 4 into the recursive formula

f(1) = - 5 ← given

f(2) = f(1) + 7 = - 5 + 7 = 2

f(3) = f(2) + 7 = 2 + 7 = 9

f(4) = f(3) + 7 = 9 + 7 = 16

common difference d = 16 - 9 = 9 - 2 = 2 - (- 5) = 7



6 0
3 years ago
For functions f(x) = x + 2 and g(x) = 8x2 - 2x + 4,
adoni [48]

Answer:

Sorry im not ood at math so i cant help

Step-by-step explanation:

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2 years ago
Multiply (2x^2-3x+5)(x^2+4x+1)
DochEvi [55]

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Step-by-step explanation:

(2x^2-3x+5)(x^2+4x+1)\\(2x^2-12x+5)

3 0
3 years ago
Please help!!!!!
wel

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8 0
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