Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,
- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;
- Hence, the number of 25 paise coins will be <u>12</u>.
Answer:
x = -5
Explanation:
4(2x + 10) = 0
[ Simplify both sides of the equation ]
4(2x + 10) = 0
(4)(2x) + (4)(10) = 0 [Distribute]
8x + 40 = 0
[ Subtract 40 from both sides ]
8x + 40 − 40 = 0 − 40
8x = −40
[ Divide both sides by 8 ]
8x / 8 = −40 / 8
x = -5
Answer:
It’s b.
Step-by-step explanation:
To get the slope of the line, you need to points. Two points you already have are (0,0) and (-5,6). So all you need to do is plug those points into slope equation (y1-y2 over x1-x2) 0-6 over 0+5 equals -6/5. The slope equals -6/5, and when you plug it into y=mx+b it equals y=-6/5x. Which is b.