Question

Graph a line with a slope of 4 that contains the point (3,0). FOR 100 POINTS PLS

Answer 1

Answer:

Hi there!

Recall that slope-intercept form is:

y = mx + b

Where m = slope

In this instance, we are given a slope of 4,

therefore:

y = 4x + b

Substitute in the x and y coordinates of the point given:

0 = 4(3) + b

0 = 12 + b

Substract 12 from both side:

-12 = b

Therefore, the equation would be:

y = 4x - 12

Graph the equation by finding x and y values or using a calculator:

x = 0, y = 4(0) - 12 = 12 (0, 12)

x = 1, y = 4(1) - 12 = - 8 (1, -8)

x = 2, y = 4(2) - 12 = - 4 (2, -4)

x = 3, y = 4(3) - 12 = 0 (3, 0)

And so forth:

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