Here for 120, the expression for the start root and end root is given
<h3>What will be the expression for start root and enroot of 120?</h3>
Here we need to find 
By simplifying the given expression, we get:
by taking square roots on both sides we get
Thus for 120, the expression for the start root and end root is given
To know more about the Square roots follow
brainly.com/question/124481
Answer:
The triangle has one solution. The remaining side c ≈ 4 and remaining angles B = 30°; C = 31°.
Option D is correct.
Step-by-step explanation:
if angle A is obtuse and if a > b then the triangle has one solution
We are given ∠ = 119° which is obtuse and side a= 7 and side b - 4 i.e 7>4 so, the triangle has one solution.
Finding remaining side c and ∠B and ∠C
Using Law of sines to find ∠B
a/sin A = b/sin B
7/sin 119° = 4/sin B
7 * sin B = 4 * sin 119
7*sin B = 4(0.874)
sin B = 3.496/7
B = sin^-1(0.4994)
B = 29.96 = 30°
We know that sum of angles of triangle = 180°
So, 180° = 119° + 30° +∠C
180° = 149° + ∠C
=> ∠C = 180° - 149°
∠C = 31°
Now finding c
b/sin B = c /sin C
4/Sin 30 = c/sin 31
4* sin 31 = c*sin 30
4*0.515 = c* 0.5
=> c = 4*0.515/0.5
c = 4.12 ≈ 4
So, Option D one solution; c ≈ 4; B = 30°; C = 31° is correct.
These are the points graphed:
Are they equal? Yes.
Answer:
Rectangle: 112m
Trapezoid: 28m
Step-by-step explanation:
The area of the rectangle is 8*14, which is 112. The area of the trapezoid is ((base1 + base2)* height)/2. That is ((4+10)*4)/2, which is 28.
