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Crazy boy [7]
3 years ago
7

Can someone help me with this math problem?

Mathematics
1 answer:
skad [1K]3 years ago
3 0

1\ mi-\dfrac{2}{3}\ mi=\dfrac{3}{3}\ mi-\dfrac{2}{3}\ mi=\dfrac{1}{3}\ m

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torisob [31]

Answer:

3) yes, it is in the shaded region

4) no, it lies on a less-than line

5) yes, it lies on a greater-than-or-equal-to line

6) no, it isnt in the shaded region

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
X^3 - 2y^2 - 3x^3 + z^4
Andreyy89

Answer:

-2x³ - 2y² + z⁴

Step-by-step explanation:

Step 1: Write out expression

x³ - 2y² - 3x³ + z⁴

Step 2: Combine like terms (x³)

-2x³ - 2y² + z⁴

8 0
3 years ago
Which is greater 150 ounces or 5 pounds
inysia [295]
The greater is 150 ounces
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3 years ago
Help help help math math help
Eddi Din [679]

Answer:

x = - 4

Step-by-step explanation:

i hope its helped. thank you !

3 0
2 years ago
Find the nth maclaurin polynomial for the function. f(x) = 5x − 5 x + 1 , n = 4 p4(x)
zysi [14]
Assuming the function is f(x)=\dfrac{5x-5}{x+1}, and not 5x-5x+1=1 which would be its own Maclaurin polynomial right away.

\dfrac{5x-5}{x+1}=\dfrac{5(x-1)}{x+1}=\dfrac{5(x+1-2)}{x+1}=5-\dfrac{10}{1+x}

Recall the geometric power series,

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

where |x|. Replace x\mapsto-x and we have

\displaystyle\sum_{n=0}^\infty (-x)^n=\frac1{1+x}

and so

f(x)=5-10\displaystyle\sum_{n=0}^\infty(-x)^n

We want the 4th degree polynomial, so

p_4(x)=-5+10x-10x^2+10x^3-10x^4
7 0
3 years ago
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