Question

The ages of four cousins are consecutive integers. Let the integers equal n, n+1, n+2 and n +3. The sum of their ages is 34 How old is the oldest
cousin?
____ years old​

Answer 1

Answer:

10

Step-by-step explanation:

n + n+1 + n+2 + n+3 = 4n + 6

4n + 6 = 34

4n = 28

n = 7

Eldest: n + 3 = 7 + 3 = 10

Answer 2

Answer:

Ages are: 7, 8, 9 and 10.

The age of the eldest cousin is '10'

Step-by-step explanation:

Age of four cousins are:

$n$, $n+1$ , $n+2$ and $n +3$

Sum of their ages is 34

So,            $n$+($n+1$ )+($n+2$) + ($n +3$)=34

                $n+(n+1)+(n+2)+(n+3)=34\\\\n+n+1+n+2+n+3=34\\\\4n+6=34\\\\4n=34-6\\\\4n=28\\\\n=\frac{28}{4}\\\\ n=7$

So the ages are:

$n=7\\n+1=7+1=8\\n+2=7+2=9\\n+3=7+3=10$

The age of the eldest cousin is '10'