Answer:
Step-by-step explanation:
The existence of a unit rate implies that you have TWO variables. Here you list only one: $.
If you pay $2.98 for 6 units of something, such as pieces of fruit, then the unit rate would be:
$2.98
----------------------- = $0.50/piece
6 pieces of fruit
the total mass in kilograms y of the cinder block and brick is 
.
<u>Step-by-step explanation:</u>
Here we have , A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick has a mass of 0.6 kilogram. We need to find What is the total mass in kilograms y of the cinder block and brick . Let's find out :
According to given data in question ,
⇒ 
⇒ 
A cinder block weighs x pounds and a brick has a mass of 0.6 kilogram . Let total mass in kg of the cinder block and brick is y , i.e.
⇒ 
⇒ 
⇒
Therefore , the total mass in kilograms y of the cinder block and brick is .
Answer:
Approximately, 6.283..
Step-by-step explanation:
First calculate the area of the whole circle
We have radius(r)=4 cm
Area of circle(a)=pir^2
=pi×(4)^2
=pi×16
=Approximately,50.265......
A cirlce has a total of 360 degrees
Therefore,we can conclude 360 degrees=50.265...
or,1 degree=50.265/360
1 degree=Approximately,0.139
Now,
Area for the shaded region = Area of 45 degree
=0.139×45=Approximately,6.283.....
Therefore,the area of the shaded region is approximately,6.283....
Answer:
Part A: impossible
Part B: Either equal or blue
Part C: 9 green and 2 blue were added
Step-by-step explanation:
Part A:
The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.
Part B:
I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.
Part C:
The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.
I hope this helps and please mark me as brainliest!
