What are 5 consecutive odd integers of 445
1 answer:
Answer:
87,88,89,90,91,92
Step-by-step explanation:
to find the answer to this math problem you set up the equation like this:
x+x+1+x+2+x+3+x+4=445
then combine like terms:
5x+10=445
then solve
5x+10=445
-10 -10
----------------------
5x=435
then divide both sides by 5
x=87
and because there are 5 consecutive terms...
87,88,89,90,91,92
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