Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

So we apply chain rule:
=

Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
Answer:
A)7.5
Step-by-step explanation:
you divide 62 by 4 and you get A
Answer:
a = - 6
Step-by-step explanation:
Given
f(x) = 3x + 5 , then
f(a) = 3a + 5 and f(a) = - 13 , then equating the right sides
3a + 5 = - 13 ( subtract 5 from both sides )
3a = - 18 ( divide both sides by 3 )
a = - 6
You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.
If the
coefficient is 1, i.e. the equation is written like
, then you can say the following about the coefficients b and c:
is the opposite of the sum of the roots
is the multiplication of the roots.
So, for example, if we want an equation whose roots are 4 and -2, we have:
So, the equation is 
If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:
And so the equation is

In order to have integer coefficients, you can multiply both sides of the equation by 8:
