All categories

4 years ago

Which of the vectors below is the sum of vectors a and b, shown here?

Mathematics

1 answer:

Fofino [41]4 years ago

7 0

Answer:

Option C

Step-by-step explanation:

To answer this question you must use the parallelogram method shown in the attached image.

To answer this question, use the parallelogram method as shown in the attached image.

-Place the vectors a and b at the same point of origin.

-On the tip of the vector b draws a vector a.

-On the tip of vector a to draw a vector b.

-Draw a vector "f" that goes from the origin to the corner of the parallelogram.

The vector "f" represents the sum of the vector a with the vector b.

The correct option is C

You might be interested in

Find the slope that passes through these two points.

barxatty [35]

Answer:

$m = \frac{ - 1 - 4}{2 + 3} \\ m = - 1$

Good luck!

Intelligent Muslim,

From Uzbekistan.

5 0

4 years ago

What is the square root of 36 squared

Grace [21]

36;
the square root and the square cancel out, or you can work it out and say
((36)^1/2)^2 = (6)^2= 36

4 0

4 years ago

Read 2 more answers

750/1000 in simplest form

Virty [35]

750/1000
Divide both numbers by 50. You get 15/20

3 0

3 years ago

the width of a rectangule is 4 feet and the diagonal length of the rectangle is 13 feet, which mesurment is closest to the lengt

3241004551 [841]

Answer:

52 feet

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the

Temka [501]

1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.

7 0

3 years ago