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2 years ago

Find the volume of each figure. Round your answers to the nearest tenth, if necessary

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

5 0

Answer:

1.92 m³

hopefully this answer can help you to answer the next question.

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If all squares are rectangles, and if all rectangles are parallelograms, then all squares are parallelograms. Which law of prope

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Symmetric property, I remembered the answer for this for my summer school. This is one of the equivalence properties of equality.

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3 years ago

What is the thirty-second term of the arithmetic sequence -12, -7, -2, 3, ... ? Show your work.

anzhelika [568]

The thirty-second term is 143

Further explanation:

As it is already given that the given sequence is an arithmetic sequence

We have to find the common difference first

So,

$a_1=-12\\a_2=-7\\a_3=-2\\a_4=3$

$d=a_2-a_1=-7-(-12)=-7+12=5\\a_3-a_2=-2-(-7)=-2+7=5$

The common difference is 5.

And first term is -12

The explicit formula for arithmetic sequence is:

$a_n=a_1+(n-1)d\\Here,\\a_n\ is\ nth\ term\\a_1\ is\ first\ term\\d\ is\ common\ difference$

Putting the values in the formula

$a_n=-12+(n-1)(5)\\a_n=-12+5n-5\\a_n=-17+5n$

Putting n=32 in explicit formula

$a_{32}=-17+5(32)\\=-17+160\\=143$

The thirty-second term is 143

Keywords: Common difference, Arithmetic Sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

6 0

2 years ago

Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?

Korvikt [17]

Answer:

$5\sqrt{2}$ units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

$\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2$

Substituting our given values in above equation we will get,

$\text{Hypotenuse}^2=5^2+5^2$

$\text{Hypotenuse}^2=25+25$

$\text{Hypotenuse}^2=50$

Upon taking square root of both sides of our equation we will get,

$\text{Hypotenuse}=\sqrt{50}$

$\text{Hypotenuse}=\sqrt{25*2}$

$\text{Hypotenuse}=5\sqrt{2}$

Therefore, the length of hypotenuse of triangle ABC is $5\sqrt{2}$ units.

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3 years ago

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The top graph is correct because an x=# will create a vertical line at that #

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2 years ago

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4.07065 in words or written form?

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Four and seven thousand sixty-five hundred thousandths, I believe

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3 years ago

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Find the volume of each figure. Round your answers to the nearest tenth, if necessary​

Find the volume of each figure. Round your answers to the nearest tenth, if necessary