Answer:
<h2>
31.7 cm^2</h2>
Solution,
In ∆ ABC
< A + <B + < C = 180°
or, 72 + 59 + <C = 180°
or, 131 + <C = 180°
or, <C = 180 - 131
< C = 49
Area of ∆ABC = 1/2 ab sin C
= 1/2 * 12 * 7 * sin 49
= 42 * sin 49
= 31.7 ( approximately)
Hope this helps...
Good luck on your assignment...
Answer:
6(y+1.5)=-18
6y+9=-18 -9
6y=-27 ÷6
y=-4.5
Step-by-step explanation:
prove me wrong
Answer:
i think both of them cant be
Answer:
Step-by-step explanation:
The triangles are drawn below.
CD is perpendicular to AB as CD is height to AB.
Therefore, angles 
°
So, triangles ΔCBD and ΔCAD are right angled triangles.
Now, from the right angled triangle ΔABC,
From ΔCBD,
is same as 
.
So, 
Now, from ΔCAD,
is same as 
So, 
Hence, the unknown angles of both the triangles are:
<span>0.827 = 0.827 / 1
Numerator = 0.827 × 10 × 10 × 10 = 827
Denominator = 1 × 10 × 10 × 10 = 1000
Numerator / Denominator = 827 / 1000
Simplifying our fraction
= 827/1000
= 827/1000</span>
