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FrozenT [24]
3 years ago
8

Solve by factoring and show work x^2-3x-10=0

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0
The first rule of factoring is to try to factor a common factor from all the terms. In this case, there is no common factor.

Now we factor the trinomial.
This quadratic trinomial is of the form
x^2 + ax + b = 0
where the coefficient of the x^2 term is 1.
To factor it, find two numbers that multiply to "b", the constant term,
and add to "a", the coefficient of x.

The numbers are -5 and 2 since -5 * 2 = -10, and -5 + 2 = -3.

Now we write two sets of parentheses with x on the left side:

(x      )(x       ) = 0

We fill in the parentheses with the two numbers we found above, -5 and 2.

(x - 5)(x + 2) = 0

That is the factoring.
sergij07 [2.7K]3 years ago
3 0
Hello there!

x^2 - 3x - 10=0

Factorize the left side 

(x + 2)(x-5)=0 

Set factors equal to 0

x + 2 = 0 or x - 5 = 0 

x = -2 or x = 5 

Best of luck!
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Doug is in line at the store. He has three items that cost ​$4.50​, ​$3.05​, and ​$1.50. Explain how Doug can add the cost of th
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Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)
ohaa [14]

Answer:

Perpendicular

<em />

Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

D = (-2, 13)

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10 - 8}{4 - (-4)}

m = \frac{10 - 8}{4 +4}

m = \frac{2}{8}

m = \frac{1}{4}

For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

m = \frac{12}{-3}

m = -4

For Lines to be parallel, the slope must be equal:

i.e. m_1 = m_2

This condition is not true because:

\frac{1}{4} \neq -4

For Lines to be perpendicular, the slope must be:

m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

6 0
3 years ago
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