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4 years ago

I really need some help on this question please!

Mathematics

1 answer:

madam [21]4 years ago

3 0

Answer:

2.5

Step-by-step explanation:

I used the process of elimination :

For A and B, you can't have a negative number since it is a positive correlation

For C, 1 as a slope isn't reasonable

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Find the next term in the series:

guapka [62]

Answer:

Step-by-step explanation:

This is called the Tribonacci sequence. In this sequence, you add the last 3 numbers together to get the next number in the sequence.

For example, 0+1+1=2, 1+2+4=7, 4+7+13=24 and so on.

7+13+24=44

44 is the next number in the sequence

5 0

3 years ago

I need help with this worksheet I don't understand from 12-14

siniylev [52]

Answer:

13.jawaban nya

14.jawaban nya

15.jawaban nya

3 0

3 years ago

Samir harvest the peppers and pumpkins in his garden he picks 3 5/8 less peppers in the afternoon than in the evening if Samir p

tatuchka [14]

<h2>Hello!</h2>

The answer is:

Samir picks $7\frac{9}{8} Kg$ of peppers in the evening.

To solve this problem, we must remember the way to add or subtract mixed numbers.

We must remember the way of adding or subtracting fractions:

$\frac{a}{b}+\frac{c}{d} =\frac{ad+bc}{bd}$

Also, if we need to add or subtract mixed numbers with different denominators, we need to follow the next steps:

- Add or subtract the whole number part

- Add or subtract the fractional numbers.

- Put together both, whole number addition or subtraction result and the addition or subtraction of the fractional numbers.

So,

$a\frac{b}{c}+d\frac{e}{f} =(a+d)\frac{bf+ce}{cf}$

Now, if Samir picks 3 5/8 less peppers in the afternoon than in the evenning, and if he picks 4 3/6 peppers in the afternoon, so:

Let be x the number of peppers that he picks in the evening, so:

$x-3\frac{5}{8}x=4\frac{3}{6}\\\\x=4\frac{3}{6}+3\frac{5}{8}$

Then, simplifying we have:

$x=4\frac{3}{6}+3\frac{5}{8}\\\\x=4\frac{3}{6}+3\frac{5}{8}=(4+3)\frac{24+30}{48}\\\\x=(4+3)\frac{24+30}{48}=7\frac{54}{48}=7\frac{9}{8}$

So, Samir picks $7\frac{9}{8} Kg$ of peppers in the evening.

Have a nice day!

6 0

4 years ago

cylinder with height 9 inches and radius is filled with water, it can fill a certain pitcher. How many of these pitchers can a c

larisa [96]

Answer:

Step-by-step explanation:

The 1st cylinder used to fill the pitcher has:

height:

h = 9 in

radius:

r = r

The volume of a cylinder is given by:

$V=\pi r^2 h$

Therefore, the volume of the 1st cylinder is

$V=\pi r^2 9=9\pi r^2$

We are told that the water inside this cylinder can fill a certain pitcher, so this is also the volume of the pitcher.

Then, we have a second cylinder, which has height

h = 9 in

and radius

r' = 2r

So the volume of this cylinder is

$V'=\pi r'^2 h = \pi (2r)^2 9 =9\pi (4r^2)=36\pi r^2$

This means that the number of pitchers that can be filled by this 2nd cylinder is

$n=\frac{V'}{V}=\frac{36\pi r^2}{9\pi r^2}=4$

8 0

4 years ago

Your flight has been delayed: At Denver International Airport, 85% of recent flights have arrived on time. A sample of 14 flight

Bezzdna [24]

Answer:

a. p=1.000

b. p=0.2924

c. p=0.7358

d. No

Step-by-step explanation:

a. This problem satisfies all the criteria for a binomial experiment expressed as:

$P(X=x){n\choose x}p^x(1-p)^{n-x}$

-Given that p=0.85, n=14, the probability that exactly all 14 were on time is calculated as:

$P(X\geq 1)=1-P(X=0)\\\\=1-{12\choose 0}0.85^0(1-0.85)^{12}\\\\=1-1.297\times 10^{-10}\\\\=1.0000$

Hence, the probability that all 12 flights are on time is 1.0000

b. Given that n=12, and p=0.85

-The probability that exactly 10 flights are on time is calculated as;

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\={12\choose 10}0.85^{10}(1-0.85)^{2}\\\\=0.2924$

Hence, the probability that exactly 10 flights are on time is 0.2924

c. Given that n=12, and p=0.85

-The probability that more of 10 or more flights are on time:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 10)=P(X=10)+P(X=11)+P(X=12)\\\\={12\choose 10}0.85^{10}(0.15)^{2}+{12\choose 11}0.85^{11}(0.15)^{1}+{12\choose 12}0.85^{12}(0.15)^{0}\\\\=0.2924+0.3012+0.1422\\\\=0.7358$

Hence, the probability of 10+ flights being on time is 0.7358

d. We first find the mean of the distribution:

$\mu=E(X)=0.85\times 14\\\\=11.9$

#We then find the probability of 11+=0.3012+0.1422=0.4434

-We compare the expectation to the probability of 11+ flights being on time.

No. Since the probability $P(X\geq 10)$ =0.4434 < that the expectation, 11.9, it is not unusual for 11+ flights to be on time.

*I have used a sample size of n=12 since there are two separate n values:

5 0

3 years ago