Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
6 -2 = 4
4 - 3 = 1
1 - .80 = .20
The Pythagorean Proposition can help you explain this:
Two solutions exist,
2(x - 1) = 8
2x - 2 = 8
2x = 10
x = 5
&
2(x + 1) = 8
2x + 2 = 8
2x = 6
x = 3
the two solutions are 5 and 3
Answer:
i believe the first one should be 20 5 since its supposed to be in expanded form but i dont know the second one sorry hope you do good
Step-by-step explanation:
