(4x^2-4x-3)+(3x^2-3x-5) then (4x^2-4x-3)-(3x^2-3x-5) show work on both mark brainliest
1 answer:
We have to add the polynomials and
To add the polynomials we need to add the like terms, by like terms we understand that the terms with the same exponent of the variables.
So in this case,
We will add the coefficients of , and constants separately, we get:
Similarly, for the polynomials
We will subtract the coefficients of like terms, we get:
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Well, a logarithmic expression is just an exponential expression written from the point of the exponent.
now, ln is just a shorthand for the logarithm with a base "e" or euler's constant, so-called the "natural logarithm", now, let's use the exponential version of that here, and let's say equals an constant exponent of "k",
now, look closely, what "k" value, what exponent, negative or fraction or positive, will ever make "e" to 0? none, so one can say is "undefined".
now, ln is just a shorthand for the logarithm with a base "e" or euler's constant, so-called the "natural logarithm", now, let's use the exponential version of that here, and let's say equals an constant exponent of "k",
now, look closely, what "k" value, what exponent, negative or fraction or positive, will ever make "e" to 0? none, so one can say is "undefined".