Question

(4x^2-4x-3)+(3x^2-3x-5) then (4x^2-4x-3)-(3x^2-3x-5) show work on both mark brainliest

Answer 1

We have to add the polynomials $(4x^2-4x-3)$ and $(3x^2-3x-5)$

To add the polynomials we need to add the like terms, by like terms we understand that the terms with the same exponent of the variables.

So in this case,

$(4x^2-4x-3)+(3x^2-3x-5)$

We will add the coefficients of $x^2, x$, and constants separately, we get:

$(4+3)x^2+(-4-3)x+(-3-5)=7x^2+(-7)x+(-8)=7x^2-7x-8$

Similarly, for the polynomials $(4x^2-4x-3)-(3x^2-3x-5)$

We will subtract the coefficients of like terms, we get:

$(4-3)x^2-(4-3)x-(3-5)=x^2-x+2$