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vesna_86 [32]
3 years ago
5

Type your response in the box. Why do many log functions (those that aren’t transformed in any manner except for a change in the

base) have the point (1,0) in common? For example, all of these functions pass through (1,0): f(x) = ln x g(x) = log x h(x) = log2 x
Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

The point (1,0) is common to all log functions of the form k(x) = logb x with any base (b). Logarithmic functions share this feature because of a property of exponents that states b0 = 1 for any value of b.

In a log function of the form k(x) = logb x, k(1) = logb 1.

So, by the definition of a logarithm, bk(1) = 1.

Applying the property of exponents to bk(1) = 1 = b0, we get k(1) = 0.

So, (1,0) is a point on the graph.

Step-by-step explanation:

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kotykmax [81]
The answer is (0,-5)
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MrRissso [65]
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3 years ago
Don't know how to solve this problem, help would be appreciated
kenny6666 [7]

Answer:

219

Step-by-step explanation:

The figure has the shape of a trapezoid. We find the area of the trapezoid and subtract the area of the rectangular door.

area of trapezoid = (base1 + base2)h/2

area of trapezoid = (20 ft + 12 ft) * 15 ft / 2

area of trapezoid = 32 ft * 15 ft /2

area of trapezoid = 240 ft^2

area of rectangle = length * width

area of rectangle = 7 ft * 3 ft

area of rectangle = 21 ft^2

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6 0
4 years ago
Will BAINLIST!!!!
Dafna11 [192]

Answer:

6.283 m

Step-by-step explanation:

2m is the length so half is the radius

the radius is 1

so if c=2\pi1

and \pi 3.14159

u get 6.283

2(3.14159) x 1 = 6.283

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7 0
3 years ago
Line DE contains the points D (–1, –4) and E (3, 3). Line FG contains the point F (–3, 3). Which set of coordinates for point G
Bond [772]

Answer:

The set of coordinates for point G that make the two lines perpendicular are given through the relation

7y = -4x + 9

Step-by-step explanation:

The condition for perpendicularly of two lines is that the products of the slope of the two lines, m₁ and m₂ must be equal to -1.

For a line whose two points (x₁, y₁) and (x₂, y₂)

on the line are known, the slope of the line, m, is given as

m = (Δy/Δx) = (y₁ - y₂) ÷ (x₁ - x₂)

points D (–1, –4) and E (3, 3).

Let the slope of DE be m₁ and the slope of FG be m₂

Since the two lines are perpendicular,

m₁m₂ = -1

m₁ = (Δy/Δx) = (-4 - 3) ÷ (-1 -3) = (7/4) = 1.75

Since, m₁m₂ = -1, this means that,

m₂ = (-1/m₁) = (-1/1.75) = -(4/7)

Let the coordinates of point G be (x, y)

m₂ = (3 - y) ÷ (-3 - x)

(-4/7) = [(3-y)/(-3-x)]

-4(-3-x) = 7(3-y)

12 + 4x = 21 - 7y

7y = -4x + 9

Hope this Helps!!!

8 0
3 years ago
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