Any number times 0 equals 0
Answer:
The height of the objects are the same after 2 seconds.
Step-by-step explanation:
In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

The height of the objects are the same after 2 seconds.
1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2
The value of the composite function is option (D) (f ∘ g)( - 1) = - 4.
The functions are given as:
f(x) = x + 1 and g(x) = 5x.
We need to find the composite function:
(f ∘ g)( - 1).
= f (g ( - 1)
Substitute value of g(x):
= f ( 5 ( - 1))
= f ( - 5)
Substitute value of f(x):
= ( - 5 ) + 1
= - 5 + 1
= - 4
Therefore, the value of the composite function is option (D) (f ∘ g)( - 1) = - 4.
Learn more about function here:
brainly.com/question/25638609
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1 1/16 is the answer!! Hope this helps! <3 x