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Alenkinab [10]
3 years ago
6

Is 0.03 greater than 0.003

Mathematics
2 answers:
luda_lava [24]3 years ago
8 0
Yes you are correct
Iteru [2.4K]3 years ago
4 0
Yes, it is because the 3 in the first one is in the hundredths place while the 3 in the second one is in the thousandths place.

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Solve the inequality. 4/5x+5<3
Marizza181 [45]
4/5x+5 is greater than 3

4 0
3 years ago
Solve for xxx.
const2013 [10]

Answer:

No solutions

Step-by-step explanation:

Solve for x the system of two inequalities:

\left\{\begin{array}{l}-9x+5

First, solve each inequality separately:

1.

-9x+5

2.

13x+25

Now, we get

x>-\dfrac{4}{3}

and

x

There are no common values for x, for which both inequalities hold, so the system of two inequalities has no solutions.

4 0
3 years ago
Witch equation has the correct sign on the product.
maria [59]

Answer: choice A or (-25)(-25)=625

Step-by-step explanation:

its choice A because a negative times a negative equals a positive :)

4 0
3 years ago
Read 2 more answers
In a school election, Juan received 4 times as many votes as Wayne, Neal recurved twenty less votes than Juan, and Kerry got hal
77julia77 [94]

Votes received by Wayne is 112

<em><u>Solution:</u></em>

To find: votes received by Wayne

Let the vote received by Wayne be "x"

<em><u>Juan received 4 times as many votes as Wayne</u></em>

Therefore,

Juan votes = 4 times as many votes as Wayne

Juan votes = 4x  ---- eqn 1

<em><u>Neal received twenty less votes than Juan</u></em>

Neal votes = twenty less votes than Juan

Neal votes = Juan votes - 20

Neal votes = 4x - 20 ---- eqn 2

<em><u>Kerry got half as many votes as Neal</u></em>

Kerry votes = half of neal votes

Kerry votes = \frac{4x - 20}{2}  ---- eqn 3

The total votes cast in the election was 1,202

Wayne votes + Juan votes + Neal votes + Kerry votes = 1202

Plug in eqn 1 , eqn 2, eqn 3

x + 4x + 4x - 20 + \frac{(4x - 20)}{2} = 1202\\\\2x + 8x + 8x - 40 + 4x - 20 = 1202 \times 2\\\\22x - 60 = 2404\\\\22x = 2404 + 60\\\\22x = 2464\\\\x = 112

Therefore votes received by Wayne is 112

4 0
3 years ago
Eight people attend the theater "together and sit in a row with exactly eight seats. Suppose the eight people consist of three m
Nata [24]

Answer:

They can be seated in 120 differents ways.

Step-by-step explanation:

Taking into account that there are 3 couples and every couple has an specific way to sit, for simplify the exercise, every couple is going to act like 1 option and it's going to occupy 1 Place. If this happens we just need to organize 5 options (3 couples and 2 singles) in 5 Places (3 for a couple and 2 for the singles)

It means that now there are just 5 Places in the row and 5 options to organized. So the number of ways can be calculated using a rule of multiplication as:

<u>      5         </u>*<u>        4          </u>* <u>       3           </u> *  <u>        2     </u>  * <u>         1         </u> = 120

 1st place    2nd Place    3rd place        4th Place    5th Place

Because we have 5 options for the 1st Place, the three couples and the 2 singles. Then, 4 options for the second Place, 3 options for the third place, 2 for the fourth place and 1 option for the 5th place.

Finally, they can be seated in 120 differents ways.

8 0
3 years ago
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