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Natalka [10]
2 years ago
15

Two of the solutions for the equation 2x + 3y = 12 are (9

Mathematics
2 answers:
hoa [83]2 years ago
8 0
Well, to solve for x, you have to isolate it. I will show how to solve it, step-by-step below:
2x+3y=12
2x+3y-3y=12-3y
2x=-3y+12 ...divide both sides by 2
x=-3/2y+6

Now, to completely solve for x, you need to find what y is equal to. But to solve for y, you have to "get rid" of the x. You can use "-3/2y+6" in place of the x.
2(-3/2y+6)+3y=12
-6/2y+12+3y=12 ...simplify
-3y+12+3y=12 ...move the 12 to the other side
-3y+12-12+3y=12-12
-3y+3y=0 ...add like things
0=0

...oh. There is no solution...

Let me try doing y first...
2x+3y=12
3y=-2x+12
y=-2/3x+4

2x+3(-2/3x+4)=12
2x-6/3x+12=12
2x-2x=0
0=0

...yo...what is going on... are you sure you gave us the right numbers... no typos?
jolli1 [7]2 years ago
5 0
X=<span><span><span>‌<span><span>−3/</span>2</span></span>‌y</span>+<span>6 is the answer to your problem I think

</span></span>
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Solve question 13. And 14. Please!! Will reward brainliest!!
SIZIF [17.4K]

Answer:

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

y = a sin ( 2t - \frac{-\pi }{3}) + 2

Step-by-step explanation:

In the first question,

amplitude = 4

Period = 4\pi

phase shift = \frac{-4\pi }{3}

Vertical shift = -2

Angular velocity , w = \frac{2\pi }{time period}

Here, w = \frac{2\pi }{4\pi } = 0.5

The general equation of a wave is

y = a sin( wt + ∅ )

Putting above values in the equation,

y = 4 sin( 0.5t - \frac{4\pi }{3} ) - 2

In the second question,

Amplitude is not given so we will take it as a.

time period = \pi

w = 2

Phase shift = \frac{-\pi }{3}

Vertical shift = 2

The equation is

y = a sin ( 2t - \frac{-\pi }{3}) + 2

5 0
3 years ago
2(-3х-6)please I need help
andrew-mc [135]

Step-by-step explanation:

2( - 3x - 6) \\   - 6x + 12

3 0
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viktelen [127]
X^2 - 10 = 3x
X^2 - 3x - 10 = 0
(x - 5) (x + 2) = 0
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