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3 years ago

13

Julia spends 2.5 on gas for her lawn mower. she earns 15.00 mowing her neighbors yard.what is julias profit

1 answer:

Natali [406]3 years ago

4 0

Her profit would be 12.50

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What is 50/90 in simplest form fraction

lisabon 2012 [21]

5/9, is what it should be

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3 years ago

On February 1, 1977, John deposited $2250 into a savings account paying 5.76% interest, compounded quarterly. If he hasn't made

Travka [436]

John's effective annual rate is about
(1 +.0576/4)^4 -1 ≈ 5.8856%
According to the "rule of 72", John's money will have doubled in
72/5.8856 = 12.23 years

John's balance will be $4500 in 1989.

_____
Since you're only concerned with the year (not the month), you don't actually need to determine the effective annual rate. The given rate of 5.76% will tell you 72/5.76 = 12.5 years. The actual doubling time is closer to 12.12 years, so using the effective rate gives results that are closer, but "good enough" is good enough in this case.

5 0

3 years ago

The width of a picnic table is 3 times its length. If the length is 5/6 yd long, what is the area of the picnic table in square

VARVARA [1.3K]

Step-by-step explanation:

Breadth

=5/6

Length

=15/6

Area of rectangle = l x b

=5/6 x 15/6

=75/6

5 0

2 years ago

Read 2 more answers

Help please it’s important!!

bixtya [17]

2

Here is the explanation: 2 (17x+2)

5 0

2 years ago

Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had

Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size $n_1$ = 49

Population standard deviation $\sigma_1$ = 3

Sample mean $\overline x _1$ = 10

<u>Second population:</u>

Sample size $n_2$ = 64

Population standard deviation $\sigma_2$ = 4

Sample mean $\overline x_2$ = 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

$\mathbf{H_o:\mu_1=\mu_2}$

$\mathbf{H_1:\mu_1\ne\mu_2}$

Level of significance = 0.01

Using the Z-test statistics;

$Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}$

$Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}$

$Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}$

$Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}$

$Z = \dfrac{-2}{\sqrt{0.43367}}$

$Z = \dfrac{-2}{0.658536}$

Z = - 3.037

Z $\simeq$ - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses $H_o$

5 0

2 years ago