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3 years ago

Find the sum of 9 and 20 on number line

Mathematics

1 answer:

Mrrafil [7]3 years ago

7 0

Answer:

Step-by-step explanation:

9 + 20

2 0

+ 9

2 9

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Jenny is taking a vacation from Florida. She travels 70 kilometers per hour for 2 hours, and 63 kilometers per hour for 5 hours.

crimeas [40]

Answer: 65 kmh

Step-by-step explanation:

70 kmh for 2 hours = 140 km.

63 kmh for 5 hours = 315 km

140 + 315 = 455/7 total hours = 65 kmh

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3 years ago

A box contains 9 pounds of sand the entire box of sand will be poured in equal amounts into 6 small bags how many bags of sand w

spayn [35]

Answer: 1 1/2

Step-by-step explanation: So you have 9 pounds and you have to distribute it out between 6 bags, so 9 divided by 6 you get 1 1/2 and so 1 1/2 pounds of sand go into each small bag

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3 years ago

Beth wants to buy a shirt that costs $40. She has a 20% discount. The sales tax is 8%.

Aleks04 [339]

Answer:

$34.56

Step-by-step explanation:

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The tax will be $0.56.

The final price of the shirt will be $34.56

6 0

3 years ago

Read 2 more answers

Question 2

Oliga [24]

Answer:

Step-by-step explanation:

you want the trinomial (x*x - 6x + __ ) to be written as a binomial squared.

So we would need to realize that the constant would be equal to (-6/2)^2 =(-3)^2 = 9

We have completed the square.

f(x) = 4*( x - 3)^2 + 20 is now in Vertex Form

6 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago