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Anna007 [38]
3 years ago
11

I need help in "Matlab' with how to "Create a column vector from 15 to -25 with a step size of 5"

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0

Answer:

x=[15:-5:-25]'

Step-by-step explanation:

In order to create a vector you need to use this command:

x = [j:i:k]'

This creates a regularly-spaced vector x using i as the increment between elements. j is the initial value and k is the final value. Besides you need to add the character ' at the end in order to convert the arrow vector in a column vector

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If y=(sec^-1x)^2, then show that x^2(x^2-1) d^2y/dx^2 + (2x^3 - x) dy/dx = 2
Arisa [49]

Step-by-step explanation:

Hope it helps you in your learning process.

8 0
3 years ago
Which of the following are solutions to the equation below?
inysia [295]

The answer is C and D

First we must make one side of the equation zero, so we subtract 7 on both sides of the equation, making the equation 9x^2 - 6x - 6 = 0

Then we will use the quadratic formula to find the answers.

using the Quadratic Formula where:

a = 9, b = -6, and c = -6

and the formula is 6 +- \sqrt{6^{2} } -4 (9)(6) /2 (9)

6 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
PLEASE HELP ILL GIVE 25 POINTS FOR IT
Naddik [55]
90/2 = 45 degrees twices
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3 0
3 years ago
URGENT! When we solve (cos²x - 1 = 0) by adding and taking the square root, how come we get the same answer when we factor (cos²
boyakko [2]

Answer:

56

Step-by-step explanation:

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